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Maximum Difference Between Even and Odd Frequency | LeetCode

We are given a string consisting of lowercase English letters. Our task is to find the maximum difference between the frequency of two characters in the string such that: One of the characters has an even frequency . The other character has an odd frequency . The difference is calculated as: odd_frequency - even_frequency We need to return the maximum possible difference between the odd and even frequencies. Example Walkthrough Let's take a couple of examples to better understand the problem: Example 1: Input: s = "aaaaabbc" Frequencies: 'a' → 5 (odd) 'b' → 2 (even) 'c' → 1 (odd) Here, the maximum odd frequency is 5 (for 'a') and the maximum even frequency is 2 (for 'b'). Therefore, the result is: maxOdd - maxEven = 5 - 2 = 3 Example 2: Input: s = "abcabcab" Frequencies: 'a' → 3 (odd) 'b' → 2 (even) 'c' → 2 (even) The maximum odd frequency is 3 (for 'a') and the maximum even fr...

Maximize Amount After Two Days of Conversions | Leetcode Question

When tackling the problem of maximizing the amount of currency after two days of conversions, we encounter an interesting graph-based problem that involves working with exchange rates between various currencies. In this article, we will explore this problem in detail, starting with the brute force approach and refining it to an optimized solution. Problem Explanation You are given a string initialCurrency (the starting currency), along with four arrays: pairs1 and rates1 : Represent exchange rates between currency pairs on Day 1. pairs2 and rates2 : Represent exchange rates between currency pairs on Day 2. The task is to maximize the amount of initialCurrency you can have after performing any number of conversions on both days. You can make conversions using Day 1 rates and then further conversions using Day 2 rates. Key Insights: Conversion rates are valid (no contradictions). Each currency can be converted back to its counterpart at a reciprocal rate (e.g., if USD -> EUR = 2....

Final Prices With a Special Discount in a Shop – LeetCode Solution Explained

When tackling coding problems, it's important to understand the problem thoroughly and work through solutions step-by-step. In this blog, we will explore the LeetCode problem "1475 Final Prices With a Special Discount in a Shop" . We'll walk through the problem statement, approach it with a beginner-friendly brute force solution, and analyze its time and space complexity. Finally, we'll discuss any possible optimizations to improve efficiency. Problem Statement You are given an integer array prices where prices[i] represents the price of the i th item in a shop. There is a special discount rule: If you buy the i th item, you receive a discount equal to prices[j] , where j is the smallest index such that j > i and prices[j] <= prices[i] . If no such j exists, you get no discount for that item. Your task is to return a new array answer , where answer[i] is the final price you pay for the i th item after applying the discount. Examples Example 1: Input: p...

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